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Popular >

y^'=y^2sin(t)

Solution

y^{^{'}} = y^{2} sin (t)

Solution

y = - \frac{1}{- cos ( t ) + c _{1}}

Solution steps

y^{'} (t) = y^{2} sin (t)

Solve separable ODE:

y = - \frac{1}{- cos ( t ) + c _{1}}

y = - \frac{1}{- cos ( t ) + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=y^2sin(t) ?
The solution for y^'=y^2sin(t) is y=-1/(-cos(t)+c_{1)}