What is (\partial)/(\partial x)(2y+xe^{xy}) ?

The answer to (\partial)/(\partial x)(2y+xe^{xy}) is e^{yx}+e^{yx}yx

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2y+xe^{xy})

\frac{\partial}{\partial x} (2 y + x e^{x y})

e^{y x} + e^{y x} y x

Solution steps

\frac{\partial}{\partial x} (2 y + x e^{x y})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (x e^{x y})

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x e^{x y}) = e^{y x} + y e^{y x} x

= 0 + e^{y x} + y e^{y x} x

Simplify

= e^{y x} + e^{y x} y x

n = 1 \sum \infty \frac{1}{2 ^{2 n - 1}}

\int \frac{k}{x ^{6}} d x

\frac{d}{d x} (\frac{1}{3} (x^{2} + 2)^{\frac{3}{2}})

\int - \frac{4000 x}{( 1 + x ^{2} )} d x

\int \frac{3}{2 + x} d x

What is (\partial)/(\partial x)(2y+xe^{xy}) ?
The answer to (\partial)/(\partial x)(2y+xe^{xy}) is e^{yx}+e^{yx}yx