What is the tangent of y=e^{3x}cos(pix),(0,1) ?

The tangent of y=e^{3x}cos(pix),(0,1) is y=3x+1

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tangent of y=e^{3x}cos(pix),(0,1)

tangent of

y = e^{3 x} cos (π x), (0, 1)

y = 3 x + 1

Solution steps

Find the slope of

y = e^{3 x} cos (π x) : \frac{d y}{d x} = 3 e^{3 x} cos (π x) - π e^{3 x} sin (π x)

Compute the slope of

y = e^{3 x} cos (π x)

(0, 1) : m = 3

Find the line with slope m=

3

and passing through

(0, 1) : y = 3 x + 1

y = 3 x + 1

\frac{\partial}{\partial y} (sin (yz))

\int - \frac{2 x}{( x ^{2} - 2 ) ^{3}} d x

\int \frac{2 x ^{2} - x + 3}{x} d x

h \to 0 lim (\frac{sin ( h )}{h})

y^{^{''}} - y = t

What is the tangent of y=e^{3x}cos(pix),(0,1) ?
The tangent of y=e^{3x}cos(pix),(0,1) is y=3x+1