integral of xsec(x)tan(x)

解答

\int x sec (x) tan (x) d x

x sec (x) - ln ∣ tan (x) + sec (x) ∣ + C

求解步骤

\int x sec (x) tan (x) d x

使用分布积分法

= x sec (x) - \int sec (x) d x

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= x sec (x) - ln ∣ tan (x) + sec (x) ∣

解答补常数

= x sec (x) - ln ∣ tan (x) + sec (x) ∣ + C

n = 0 \sum \infty (- \frac{7}{8})^{n}

t an g e n t f (x) = - 3 x^{2}, at x = 1

t an g e n t 5 x^{3} - 3 x^{5}

x \to 0 - lim (\frac{x + 16}{x})

\int \frac{2 x + 3}{x ( x ^{2} - 4 ) ( x + 2 ) ^{2}} d x