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Popular Calculus >

area y=1-x^2,y=x^2-1

Solution

area

y = 1 - x^{2}, y = x^{2} - 1

Solution

\frac{8}{3}

+1

Decimal

2.66666 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} 1 - x^{2} - (x^{2} - 1) d x

Solve

\int_{- 1}^{1} 1 - x^{2} - (x^{2} - 1) d x : \frac{8}{3}

The area is:

= \frac{8}{3}

Graph

Popular Examples

tangent of 1/(x+3)

t an g e n t \frac{1}{x + 3}

derivative of sqrt(x)(x^3-5x^2+1)

\frac{d}{d x} (x (x^{3} - 5 x^{2} + 1))

(\partial)/(\partial x)(xy^3-x^2y)

\frac{\partial}{\partial x} (x y^{3} - x^{2} y)

integral of ((sqrt(5x))/5+5/(sqrt(5x)))

\int (\frac{5 x}{5} + \frac{5}{5 x}) d x

y^{''}+y^'-12y=3e^{2x}

y^{^{''}} + y^{^{'}} - 12 y = 3 e^{2 x}

Frequently Asked Questions (FAQ)

What is area y=1-x^2,y=x^2-1 ?
The answer to area y=1-x^2,y=x^2-1 is 8/3