What is the tangent of x^3-2x^2-5x+6,\at x=2 ?

The tangent of x^3-2x^2-5x+6,\at x=2 is y=-x-2

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tangent of x^3-2x^2-5x+6,\at x=2

tangent of

x^{3} - 2 x^{2} - 5 x + 6, at x = 2

y = - x - 2

Solution steps

Find the tangent point:

(2, - 4)

Find the slope of

y = x^{3} - 2 x^{2} - 5 x + 6 : \frac{d y}{d x} = 3 x^{2} - 4 x - 5

Compute the slope of

y = x^{3} - 2 x^{2} - 5 x + 6

x = 2 : m = - 1

Find the line with slope m=

- 1

and passing through

(2, - 4) : y = - x - 2

y = - x - 2

\int 8 x^{- 9} d x

\int sin (2 θ) d θ

f (s) = \frac{1}{s ( s - 3 )}

\frac{d}{d x} (arccot (2 x))

What is the tangent of x^3-2x^2-5x+6,\at x=2 ?
The tangent of x^3-2x^2-5x+6,\at x=2 is y=-x-2