What is the integral of (e^x)/(1+2e^x) ?

The integral of (e^x)/(1+2e^x) is 1/2 ln|1+2e^x|+C

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integral of (e^x)/(1+2e^x)

\int \frac{e ^{x}}{1 + 2 e ^{x}} d x

\frac{1}{2} ln ∣ 1 + 2 e^{x} ∣ + C

Solution steps

\int \frac{e ^{x}}{1 + 2 e ^{x}} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = 1 + 2 e^{x}

= \frac{1}{2} ln ∣ 1 + 2 e^{x} ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ 1 + 2 e^{x} ∣ + C

4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 10 x

\frac{\partial}{\partial x} (e^{t - x})

t y^{^{'}} - 2 y = t^{4}

\int_{0}^{1} sin (x) e^{x} d x

\frac{1}{s} - \frac{s + 8}{s ^{2} + 8 s + 25}

What is the integral of (e^x)/(1+2e^x) ?
The integral of (e^x)/(1+2e^x) is 1/2 ln|1+2e^x|+C