What is the derivative of (x^2+4*x+2)^9 ?

The derivative of (x^2+4*x+2)^9 is 9(x^2+4x+2)^8(2x+4)

What is the first derivative of (x^2+4*x+2)^9 ?

The first derivative of (x^2+4*x+2)^9 is 9(x^2+4x+2)^8(2x+4)

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derivative of

(x^{2} + 4 \cdot x + 2)^{9}

9 (x^{2} + 4 x + 2)^{8} (2 x + 4)

Solution steps

\frac{d}{d x} ((x^{2} + 4 x + 2)^{9})

Apply the chain rule:

9 (x^{2} + 4 x + 2)^{8} \frac{d}{d x} (x^{2} + 4 x + 2)

= 9 (x^{2} + 4 x + 2)^{8} \frac{d}{d x} (x^{2} + 4 x + 2)

\frac{d}{d x} (x^{2} + 4 x + 2) = 2 x + 4

= 9 (x^{2} + 4 x + 2)^{8} (2 x + 4)

f (x) = \frac{x}{x ^{2} + 196}

f (x) = x^{2} + x + 1

x \to 1 lim (\frac{3}{x ^{3} - 1})

\frac{\partial}{\partial x} (2 (x - a))

y^{^{'}} + 7 y = 4 t

What is the derivative of (x^2+4*x+2)^9 ?
The derivative of (x^2+4*x+2)^9 is 9(x^2+4x+2)^8(2x+4)
What is the first derivative of (x^2+4*x+2)^9 ?
The first derivative of (x^2+4*x+2)^9 is 9(x^2+4x+2)^8(2x+4)