What is the derivative of y=6sqrt(8x^2+7) ?

The derivative of y=6sqrt(8x^2+7) is (48x)/(sqrt(8x^2+7))

What is the first derivative of y=6sqrt(8x^2+7) ?

The first derivative of y=6sqrt(8x^2+7) is (48x)/(sqrt(8x^2+7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = 6 8 x^{2} + 7

\frac{48 x}{8 x ^{2} + 7}

Solution steps

\frac{d}{d x} (6 8 x^{2} + 7)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (8 x^{2} + 7)

Apply the chain rule:

\frac{1}{2 8 x ^{2} + 7} \frac{d}{d x} (8 x^{2} + 7)

= \frac{1}{2 8 x ^{2} + 7} \frac{d}{d x} (8 x^{2} + 7)

\frac{d}{d x} (8 x^{2} + 7) = 16 x

= 6 \cdot \frac{1}{2 8 x ^{2} + 7} \cdot 16 x

Simplify

6 \cdot \frac{1}{2 8 x ^{2} + 7} \cdot 16 x : \frac{48 x}{8 x ^{2} + 7}

= \frac{48 x}{8 x ^{2} + 7}

y = x x

(y - x + x y cot (x)) d x + x d y = 0

\int \frac{1}{x} \cdot e^{2 x^{2}} d x

\int x^{3} 9 + x^{2} d x

\int 5 sin (8 x) cos (5 x) d x

What is the derivative of y=6sqrt(8x^2+7) ?
The derivative of y=6sqrt(8x^2+7) is (48x)/(sqrt(8x^2+7))
What is the first derivative of y=6sqrt(8x^2+7) ?
The first derivative of y=6sqrt(8x^2+7) is (48x)/(sqrt(8x^2+7))