What is the d/(dt)(2cos(t)) ?

The d/(dt)(2cos(t)) is -2sin(t)

What is the first d/(dt)(2cos(t)) ?

The first d/(dt)(2cos(t)) is -2sin(t)

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\frac{d}{d t} (2 cos (t))

- 2 sin (t)

Solution steps

\frac{d}{d t} (2 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 2 (- sin (t))

Simplify

= - 2 sin (t)

\frac{\partial}{\partial z} (ln (z))

d er i v a t i v e f (x) = cos (x) + sin (x)

\frac{d x}{d y} = 4 (x^{2} + 1), x (\frac{π}{4}) = 1

\int_{1}^{6} \frac{x ^{2} + 5}{7 x - x ^{2}} d x

l a pl a ce t r an s f or m \frac{cos ( 7 t )}{e ^{5 t}}