What is the derivative of-x^2-4x-2 ?

The derivative of-x^2-4x-2 is -2x-4

What is the first derivative of-x^2-4x-2 ?

The first derivative of-x^2-4x-2 is -2x-4

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\frac{d}{d x} (- x^{2} - 4 x - 2)

- 2 x - 4

Solution steps

\frac{d}{d x} (- x^{2} - 4 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (2) = 0

= - 2 x - 4 - 0

Simplify

= - 2 x - 4

\int cosh (0)

\int_{0}^{\frac{π}{3}} tan^{2} (x) d x

t an g e n t y = 2 x^{3} - x^{2} + 2, (1, 3)

\int 1 - 4 x^{2} d x

x \to 0 lim (\frac{1}{x} - \frac{1}{x ^{2} + 1})

What is the derivative of-x^2-4x-2 ?
The derivative of-x^2-4x-2 is -2x-4
What is the first derivative of-x^2-4x-2 ?
The first derivative of-x^2-4x-2 is -2x-4