en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of-2y^2+2

Solution

\int_{- 1}^{1} - 2 y^{2} + 2 d y

Solution

\frac{8}{3}

+1

Decimal Notation

2.66666 \dots

Solution steps

\int_{- 1}^{1} - 2 y^{2} + 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{1} 2 y^{2} d y + \int_{- 1}^{1} 2 d y

\int_{- 1}^{1} 2 y^{2} d y = \frac{4}{3}

\int_{- 1}^{1} 2 d y = 4

= - \frac{4}{3} + 4

Simplify

- \frac{4}{3} + 4 : \frac{8}{3}

= \frac{8}{3}

Popular Examples

y^{''}+18y^'+80y=0

y^{^{''}} + 18 y^{^{'}} + 80 y = 0

integral from 0 to 1 of (25)/(x^5)

\int_{0}^{1} \frac{25}{x ^{5}} d x

integral from-3 to 0 of 9/(9x+4)

\int_{- 3}^{0} \frac{9}{9 x + 4} d x

integral of (20)/(1+x^2)

\int \frac{20}{1 + x ^{2}} d x

sum from n=1 to infinity of 1/(ln(n))

n = 1 \sum \infty \frac{1}{ln ( n )}

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of-2y^2+2 ?
The integral from-1 to 1 of-2y^2+2 is 8/3