What is the integral of (\sqrt[4]{x^3}) ?

The integral of (\sqrt[4]{x^3}) is 4/7 x^{7/4}+C

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integral of (\sqrt[4]{x^3})

\int (4 x^{3}) d x

\frac{4}{7} x^{\frac{7}{4}} + C

Solution steps

\int 4 x^{3} d x

4 x^{3} = x^{\frac{3}{4}},

assuming

x \geq 0

= \int x^{\frac{3}{4}} d x

Apply the Power Rule

= \frac{4}{7} x^{\frac{7}{4}}

Add a constant to the solution

= \frac{4}{7} x^{\frac{7}{4}} + C

\int \frac{10}{( x - 1 ) ( x ^{2} - 9 )} d x

t an g e n t f (x) = 1 + cos (x), at x = \frac{π}{2}

d er i v a t i v e f (x) = x cos (x)

\int \frac{1}{( x + 1 ) x} d x

\frac{\partial}{\partial t} (\frac{1}{t})

What is the integral of (\sqrt[4]{x^3}) ?
The integral of (\sqrt[4]{x^3}) is 4/7 x^{7/4}+C