What is the integral of e^{-jwt} ?

The integral of e^{-jwt} is -1/(wj)e^{-wjt}+C

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integral of e^{-jwt}

\int e^{- j wt} d t

- \frac{1}{w j} e^{- w j t} + C

Solution steps

\int e^{- j wt} d t

Apply u-substitution

= \int - \frac{e ^{u}}{w j} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{w j} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - \frac{1}{w j} e^{u}

Substitute back

u = - w j t

= - \frac{1}{w j} e^{- w j t}

Add a constant to the solution

= - \frac{1}{w j} e^{- w j t} + C

\int_{- 1}^{2} (x^{4} - 2 x^{3} + 2) d x

d er i v a t i v e (7 x + 6)^{3}

\int_{1}^{2} \frac{2}{5} x (x + 1) d x

x \to 15 lim (\frac{x ^{2}}{5} - \frac{3}{x})

\frac{d}{d x} (\frac{x ^{2}}{1 + 2 x})

What is the integral of e^{-jwt} ?
The integral of e^{-jwt} is -1/(wj)e^{-wjt}+C