What is the tangent of-2sin(x) ?

The tangent of-2sin(x) is y=-2cos(a_{0})x-2sin(a_{0})+2a_{0}cos(a_{0})

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tangent of-2sin(x)

tangent of

- 2 sin (x)

y = - 2 cos (a_{0}) x - 2 sin (a_{0}) + 2 a_{0} cos (a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 2 sin (a_{0}))

Find the slope of

y = - 2 sin (x) : \frac{d y}{d x} = - 2 cos (x)

Compute the slope of

y = - 2 sin (x)

x = a_{0} : m = - 2 cos (a_{0})

Find the line with slope m=

- 2 cos (a_{0})

and passing through

(a_{0}, - 2 sin (a_{0})) : y = - 2 cos (a_{0}) x - 2 sin (a_{0}) + 2 a_{0} cos (a_{0})

y = - 2 cos (a_{0}) x - 2 sin (a_{0}) + 2 a_{0} cos (a_{0})

f (x) = x^{5} - 3 x + 4

\frac{e ^{x}}{x + 1}

x \to 1 lim (∣ x - 1 ∣)

\frac{d}{d x} (\frac{x - 2}{x})

\frac{d}{d x} (\frac{3 x}{2 y})

What is the tangent of-2sin(x) ?
The tangent of-2sin(x) is y=-2cos(a_{0})x-2sin(a_{0})+2a_{0}cos(a_{0})