What is the tangent of x^2(2.4) ?

The tangent of x^2(2.4) is y=4.8a_{0}x-(12a_{0}^2)/5

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tangent of x^2(2.4)

tangent of

x^{2} (2.4)

y = 4.8 a_{0} x - \frac{12 a _{0}^{2}}{5}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} \cdot 2.4)

Find the slope of

y = x^{2} 2.4 : \frac{d y}{d x} = 4.8 x

Compute the slope of

y = x^{2} 2.4

x = a_{0} : m = 4.8 a_{0}

Find the line with slope m=

4.8 a_{0}

and passing through

(a_{0}, a_{0}^{2} 2.4) : y = 4.8 a_{0} x - \frac{12 a _{0}^{2}}{5}

y = 4.8 a_{0} x - \frac{12 a _{0}^{2}}{5}

\int 7 x + 5 d x

\int \frac{( 2 + x )}{1 - x ^{2}} d x

x \to 3 + lim (\frac{1}{( x - 3 ) ^{2}})

\int \frac{sin ( 5 x )}{1 - cos ( 5 x )} d x

What is the tangent of x^2(2.4) ?
The tangent of x^2(2.4) is y=4.8a_{0}x-(12a_{0}^2)/5