What is the derivative of (2x^3-x^2+6x+1^3) ?

The derivative of (2x^3-x^2+6x+1^3) is 3(2x^3-x^2+6x+1)^2(6x^2-2x+6)

What is the first derivative of (2x^3-x^2+6x+1^3) ?

The first derivative of (2x^3-x^2+6x+1^3) is 3(2x^3-x^2+6x+1)^2(6x^2-2x+6)

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\frac{d}{d x} ((2 x^{3} - x^{2} + 6 x + 1)^{3})

3 (2 x^{3} - x^{2} + 6 x + 1)^{2} (6 x^{2} - 2 x + 6)

Solution steps

\frac{d}{d x} ((2 x^{3} - x^{2} + 6 x + 1)^{3})

Apply the chain rule:

3 (2 x^{3} - x^{2} + 6 x + 1)^{2} \frac{d}{d x} (2 x^{3} - x^{2} + 6 x + 1)

= 3 (2 x^{3} - x^{2} + 6 x + 1)^{2} \frac{d}{d x} (2 x^{3} - x^{2} + 6 x + 1)

\frac{d}{d x} (2 x^{3} - x^{2} + 6 x + 1) = 6 x^{2} - 2 x + 6

= 3 (2 x^{3} - x^{2} + 6 x + 1)^{2} (6 x^{2} - 2 x + 6)

x^{2} - 9

\int_{0}^{6} 6 x + 64 d x

\int \frac{x}{( x + 1 )} d x

f (x) = \frac{4}{x + 1}, at x = 6

\int \frac{1}{2 y - 1} d y

What is the derivative of (2x^3-x^2+6x+1^3) ?
The derivative of (2x^3-x^2+6x+1^3) is 3(2x^3-x^2+6x+1)^2(6x^2-2x+6)
What is the first derivative of (2x^3-x^2+6x+1^3) ?
The first derivative of (2x^3-x^2+6x+1^3) is 3(2x^3-x^2+6x+1)^2(6x^2-2x+6)