What is the tangent of x^2+7 ?

The tangent of x^2+7 is y=2a_{0}x-a_{0}^2+7

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tangent of x^2+7

tangent of

x^{2} + 7

y = 2 a_{0} x - a_{0}^{2} + 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} + 7)

Find the slope of

y = x^{2} + 7 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} + 7

x = a_{0} : m = 2 a_{0}

Find the line with slope m=

2 a_{0}

and passing through

(a_{0}, a_{0}^{2} + 7) : y = 2 a_{0} x - a_{0}^{2} + 7

y = 2 a_{0} x - a_{0}^{2} + 7

\frac{d}{d x} (cos (x) cot (x))

\int a^{2} - x^{2} d x

e^{- 2 t} cos (4 t)

x = 5 - 5 y^{2}, x = 5 y^{2} - 5

\frac{d}{d x} ((tan (- 1 (7 x))) 2)