What is the integral from 0 to 3 of (-x^3+3x^2-2) ?

The integral from 0 to 3 of (-x^3+3x^2-2) is 3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of (-x^3+3x^2-2)

\int_{0}^{3} (- x^{3} + 3 x^{2} - 2) d x

\frac{3}{4}

Decimal Notation

0.75

Solution steps

\int_{0}^{3} - x^{3} + 3 x^{2} - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} x^{3} d x + \int_{0}^{3} 3 x^{2} d x - \int_{0}^{3} 2 d x

\int_{0}^{3} x^{3} d x = \frac{81}{4}

\int_{0}^{3} 3 x^{2} d x = 27

\int_{0}^{3} 2 d x = 6

= - \frac{81}{4} + 27 - 6

Simplify

- \frac{81}{4} + 27 - 6 : \frac{3}{4}

= \frac{3}{4}

\int (\frac{3}{x ^{5}}) d x

\frac{d}{d x} (e^{- 7 x} cos (7 x))

y = 2 x^{2} + 5, (- 1, 7)

f (x) = x^{2} e^{x} - 2 x e^{x} + 2 e^{x}

\int tan^{4} (5 t) d t

What is the integral from 0 to 3 of (-x^3+3x^2-2) ?
The integral from 0 to 3 of (-x^3+3x^2-2) is 3/4