What is the solution for (dy)/(dx)=ye^{-x^2},y(4)=1 ?

The solution for (dy)/(dx)=ye^{-x^2},y(4)=1 is y=e^{(1.77245…\erf(x)-1.77245…)/2}

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(dy)/(dx)=ye^{-x^2},y(4)=1

\frac{d y}{d x} = y e^{- x^{2}}, y (4) = 1

y = e^{\frac{1.77245 \dots erf ( x ) - 1.77245 \dots}{2}}

Solution steps

\frac{d y}{d x} = y e^{- x^{2}}

Solve separable ODE:

y = e^{\frac{1.77245 \dots erf ( x ) - 1.77245 \dots}{2}}

y = e^{\frac{1.77245 \dots erf ( x ) - 1.77245 \dots}{2}}

y^{2} \frac{d y}{d x} = 3 x^{2} y^{3} - 6 x^{2}

\int sin^{5} (6 x) d x

l a pl a ce t r an s f or m sin (6 t)

f (x) = cos (7 x)

e x p an d \frac{x ^{2}}{5 ( 1 - x )}

What is the solution for (dy)/(dx)=ye^{-x^2},y(4)=1 ?
The solution for (dy)/(dx)=ye^{-x^2},y(4)=1 is y=e^{(1.77245…\erf(x)-1.77245…)/2}