What is the tangent of f(x)= 3/(x+5),\at x=2 ?

The tangent of f(x)= 3/(x+5),\at x=2 is y=-3/49 x+27/49

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tangent of f(x)= 3/(x+5),\at x=2

tangent of

f (x) = \frac{3}{x + 5}, at x = 2

y = - \frac{3}{49} x + \frac{27}{49}

Solution steps

Find the tangent point:

(2, \frac{3}{7})

Find the slope of

f (x) = \frac{3}{x + 5} : \frac{df ( x )}{d x} = - \frac{3}{( x + 5 ) ^{2}}

Compute the slope of

f (x) = \frac{3}{x + 5}

x = 2 : m = - \frac{3}{49}

Find the line with slope m=

- \frac{3}{49}

and passing through

(2, \frac{3}{7}) : y = - \frac{3}{49} x + \frac{27}{49}

y = - \frac{3}{49} x + \frac{27}{49}

\frac{\partial}{\partial y} (- x - sin (y^{2}))

\int x^{3} (x - 1)^{- 4} d x

\frac{s ^{4}}{s}

f (x) = 3 x^{2} + 3 x + 4

- x^{2} + 6 x

What is the tangent of f(x)= 3/(x+5),\at x=2 ?
The tangent of f(x)= 3/(x+5),\at x=2 is y=-3/49 x+27/49