What is the solution for derivative of f(x)=(12)/((3x-4)^5) ?

The solution for derivative of f(x)=(12)/((3x-4)^5) is f(x)=-1/((3x-4)^4)+c_{1}

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derivative of f(x)=(12)/((3x-4)^5)

\frac{d}{d x} f (x) = \frac{12}{( 3 x - 4 ) ^{5}}

f (x) = - \frac{1}{( 3 x - 4 ) ^{4}} + c_{1}

Solution steps

\frac{df}{d x} = \frac{12}{( 3 x - 4 ) ^{5}}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{12}{( 3 x - 4 ) ^{5}} d x

\int \frac{12}{( 3 x - 4 ) ^{5}} d x = - \frac{1}{( 3 x - 4 ) ^{4}} + c_{1}

f (x) = - \frac{1}{( 3 x - 4 ) ^{4}} + c_{1}

\int \frac{- 2}{z ^{3}} d z

y^{^{''}} + 4 y^{^{'}} + 5 y = 15 x + e^{- x}

\frac{d}{d x} (\frac{sin ( x )}{1 + sin ( x )})

\int_{1}^{\infty} (\frac{1}{x ^{3}}) d x

l a pl a ce t r an s f or m 4 t^{2} cos (2 t) + 5 t e^{- 7 t}

What is the solution for derivative of f(x)=(12)/((3x-4)^5) ?
The solution for derivative of f(x)=(12)/((3x-4)^5) is f(x)=-1/((3x-4)^4)+c_{1}