What is the integral from 1 to 5 of 1/(x^2) ?

The integral from 1 to 5 of 1/(x^2) is 4/5

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integral from 1 to 5 of 1/(x^2)

\int_{1}^{5} \frac{1}{x ^{2}} d x

\frac{4}{5}

Decimal Notation

0.8

Solution steps

\int_{1}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{5}

= [- \frac{1}{x}]_{1}^{5}

Compute the boundaries:

\frac{4}{5}

= \frac{4}{5}

\int (3 x^{2} + 1) d x

\frac{1}{( x - 1 )}

\int (x^{2} + 2 x) e^{x^{3} + 3 x^{2} - 1} d x

f (x) = (x - 1)^{2} + 1, at x = - 1

f (x) = - 10 x + 5, (1, 2)

What is the integral from 1 to 5 of 1/(x^2) ?
The integral from 1 to 5 of 1/(x^2) is 4/5