What is the solution for y^'+2/t y=(cos(t))/(t^2),y(pi)=0 ?

The solution for y^'+2/t y=(cos(t))/(t^2),y(pi)=0 is y=(sin(t))/(t^2)

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y^'+2/t y=(cos(t))/(t^2),y(pi)=0

y^{^{'}} + \frac{2}{t} y = \frac{cos ( t )}{t ^{2}}, y (π) = 0

y = \frac{sin ( t )}{t ^{2}}

Solution steps

y^{'} (t) + \frac{2}{t} y = \frac{cos ( t )}{t ^{2}}

Solve linear ODE:

y = \frac{sin ( t )}{t ^{2}}

y = \frac{sin ( t )}{t ^{2}}

\frac{1}{3 x + 5}

\int - 25 cos (- 5 t) d t

x \to - 1 lim (\frac{2}{x + 1})

2^{t^{3}}

What is the solution for y^'+2/t y=(cos(t))/(t^2),y(pi)=0 ?
The solution for y^'+2/t y=(cos(t))/(t^2),y(pi)=0 is y=(sin(t))/(t^2)