What is the tangent of x^2+y^2=169,(-5,12) ?

The tangent of x^2+y^2=169,(-5,12) is y= 5/12 x+169/12

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tangent of x^2+y^2=169,(-5,12)

tangent of

x^{2} + y^{2} = 169, (- 5, 12)

y = \frac{5}{12} x + \frac{169}{12}

Solution steps

Find the slope of

x^{2} + y^{2} = 169 : \frac{d y}{d x} = - \frac{x}{y}

Compute the slope of

x^{2} + y^{2} = 169

(- 5, 12) : m = \frac{5}{12}

Find the line with slope m=

\frac{5}{12}

and passing through

(- 5, 12) : y = \frac{5}{12} x + \frac{169}{12}

y = \frac{5}{12} x + \frac{169}{12}

1 - 2 t

x \to \infty lim (π x)

\frac{d}{d x} (x f (x) + f (x) (c x) + c f (x))

\int_{1}^{2} - x + \frac{85}{50} d x

What is the tangent of x^2+y^2=169,(-5,12) ?
The tangent of x^2+y^2=169,(-5,12) is y= 5/12 x+169/12