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Popular >

2xy^'-8y=x^{-4}

Solution

2 x y^{^{'}} - 8 y = x^{- 4}

Solution

y = - \frac{1}{16 x ^{4}} + c_{1} x^{4}

Solution steps

2 x y^{'} (x) - 8 y = x^{- 4}

Solve linear ODE:

y = - \frac{1}{16 x ^{4}} + c_{1} x^{4}

y = - \frac{1}{16 x ^{4}} + c_{1} x^{4}

Popular Examples

derivative of-1/(2sqrt(1-x))derivative of

- \frac{1}{2 1 - x}

integral of sqrt(1+t^4)

\int 1 + t^{4} d t

limit as t approaches 0 of e^{-6t}

t \to 0 lim (e^{- 6 t})

integral of (x^2-16)/(x(x+2)^3)

\int \frac{x ^{2} - 16}{x ( x + 2 ) ^{3}} d x

(\partial)/(\partial x)(-sqrt(x^2+y^2))

\frac{\partial}{\partial x} (- x^{2} + y^{2})

Frequently Asked Questions (FAQ)

What is the solution for 2xy^'-8y=x^{-4} ?
The solution for 2xy^'-8y=x^{-4} is y=-1/(16x^4)+c_{1}x^4