What is the solution for (d^2y)/(dx^2)+9y=0 ?

The solution for (d^2y)/(dx^2)+9y=0 is y=c_{1}cos(3x)+c_{2}sin(3x)

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(d^2y)/(dx^2)+9y=0

\frac{d ^{2} y}{d x ^{2}} + 9 y = 0

y = c_{1} cos (3 x) + c_{2} sin (3 x)

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 9 y = 0

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x)

6 x^{3} - tan (x)

\frac{\partial}{\partial x} (x y (1 - 7 x - 4 y))

8 cos (2 x), 8 - 8 cos (2 x), 0, \frac{π}{2}

x \to 0 + lim (x - \frac{1}{x ^{3}})

\frac{\partial}{\partial x} (ln (1 + x^{2} + e^{y} + z))

What is the solution for (d^2y)/(dx^2)+9y=0 ?
The solution for (d^2y)/(dx^2)+9y=0 is y=c_{1}cos(3x)+c_{2}sin(3x)