What is the derivative of (e^x/(x+1)) ?

The derivative of (e^x/(x+1)) is (e^xx)/((x+1)^2)

What is the first derivative of (e^x/(x+1)) ?

The first derivative of (e^x/(x+1)) is (e^xx)/((x+1)^2)

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\frac{d}{d x} (\frac{e ^{x}}{x + 1})

\frac{e ^{x} x}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) e ^{x}}{( x + 1 ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x + 1) = 1

= \frac{e ^{x} ( x + 1 ) - 1 \cdot e ^{x}}{( x + 1 ) ^{2}}

Simplify

\frac{e ^{x} ( x + 1 ) - 1 \cdot e ^{x}}{( x + 1 ) ^{2}} : \frac{e ^{x} x}{( x + 1 ) ^{2}}

= \frac{e ^{x} x}{( x + 1 ) ^{2}}

\int \frac{e ^{\frac{x}{2}}}{2} d x

n = 0 \sum \infty (- \frac{5}{8})^{n}

lo g_{e} (\frac{1}{csc ( x )})

(1 + x)^{\frac{1}{x}}

y^{^{'''}} + 10 y^{^{''}} + 25 y^{^{'}} = 0

What is the derivative of (e^x/(x+1)) ?
The derivative of (e^x/(x+1)) is (e^xx)/((x+1)^2)
What is the first derivative of (e^x/(x+1)) ?
The first derivative of (e^x/(x+1)) is (e^xx)/((x+1)^2)