What is the limit as x approaches 1 of (ln(x))/(x-1) ?

The limit as x approaches 1 of (ln(x))/(x-1) is 1

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limit as x approaches 1 of (ln(x))/(x-1)

x \to 1 lim (\frac{ln ( x )}{x - 1})

1

Solution steps

x \to 1 lim (\frac{ln ( x )}{x - 1})

Apply L'Hopital's Rule

: x \to 1 lim (\frac{\frac{1}{x}}{1})

= x \to 1 lim (\frac{\frac{1}{x}}{1})

Plug in the value

x = 1

= \frac{\frac{1}{1}}{1}

Simplify

= 1

\int - 20 x d x

t y^{^{'}} + 2 y + t = 0

\int + cos (θ) cos^{5} (sin (θ)) d θ

x^{^{'}} = \frac{1}{x ^{2}}, x (1) = 1

y = \frac{1}{a ^{2} - x ^{2}}

What is the limit as x approaches 1 of (ln(x))/(x-1) ?
The limit as x approaches 1 of (ln(x))/(x-1) is 1