What is the derivative of e^{x^4y} ?

The derivative of e^{x^4y} is e^{x^4y}(4x^3y+(dy)/(dx)x^4)

What is the first derivative of e^{x^4y} ?

The first derivative of e^{x^4y} is e^{x^4y}(4x^3y+(dy)/(dx)x^4)

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\frac{d}{d x} (e^{x^{4} y})

e^{x^{4} y} (4 x^{3} y + \frac{d y}{d x} x^{4})

Solution steps

\frac{d}{d x} (e^{x^{4} y})

Apply the chain rule:

e^{x^{4} y} \frac{d}{d x} (x^{4} y)

= e^{x^{4} y} \frac{d}{d x} (x^{4} y)

\frac{d}{d x} (x^{4} y) = 4 x^{3} y + \frac{d y}{d x} x^{4}

= e^{x^{4} y} (4 x^{3} y + \frac{d y}{d x} x^{4})

\int x^{3} (5 + x^{4})^{11} d x

\int_{x^{3}}^{x^{4}} (2 t - 1)^{3} d t

\int (3) d x

f (x) = \frac{60}{0.01 x ^{2} + 1}

\frac{d}{d x} (arctan (x^{2} + 1))

What is the derivative of e^{x^4y} ?
The derivative of e^{x^4y} is e^{x^4y}(4x^3y+(dy)/(dx)x^4)
What is the first derivative of e^{x^4y} ?
The first derivative of e^{x^4y} is e^{x^4y}(4x^3y+(dy)/(dx)x^4)