What is (\partial}{\partial x}(\frac{(x-y))/z) ?

The answer to (\partial}{\partial x}(\frac{(x-y))/z) is 1/z

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(\partial}{\partial x}(\frac{(x-y))/z)

\frac{\partial}{\partial x} (\frac{( x - y )}{z})

\frac{1}{z}

Solution steps

\frac{\partial}{\partial x} (\frac{( x - y )}{z})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z} \frac{\partial}{\partial x} (x - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z} (\frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{z} (1 - 0)

Simplify

= \frac{1}{z}

\int (sin (x) e^{2 x}) d x

\frac{d}{d x} (sin (\frac{5}{x}))

\frac{\partial}{\partial x} (x cos (z))

\frac{d}{d x} (4 x - 5 x^{\frac{9}{10}})

(3 t)^{^{'}}

What is (\partial}{\partial x}(\frac{(x-y))/z) ?
The answer to (\partial}{\partial x}(\frac{(x-y))/z) is 1/z