What is the solution for (dy)/(dx)=y^2+y ?

The solution for (dy)/(dx)=y^2+y is y=(e^{x+c_{1}})/(1-e^{x+c_{1)}}

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(dy)/(dx)=y^2+y

\frac{d y}{d x} = y^{2} + y

y = \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

Solution steps

\frac{d y}{d x} = y^{2} + y

Solve separable ODE:

y = \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

y = \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

y = arccos (x)

x \to π lim (sin (\frac{5}{3} x))

\frac{\partial}{\partial y} (x yz + x y^{4} + y z^{4} + z x^{4})

\frac{3}{s ^{2} + 2 s + 1}

y = - x^{3}, (1, - 1)

What is the solution for (dy)/(dx)=y^2+y ?
The solution for (dy)/(dx)=y^2+y is y=(e^{x+c_{1}})/(1-e^{x+c_{1)}}