What is the solution for y^{''}-2y^'+y=0,y(0)=3,y^'(0)=0 ?

The solution for y^{''}-2y^'+y=0,y(0)=3,y^'(0)=0 is y=3e^t-3e^tt

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y^{''}-2y^'+y=0,y(0)=3,y^'(0)=0

y^{^{''}} - 2 y^{^{'}} + y = 0, y (0) = 3, y^{^{'}} (0) = 0

y = 3 e^{t} - 3 e^{t} t

Solution steps

y^{''} (t) - 2 y^{'} (t) + y = 0

Solve linear ODE:

y = 3 e^{t} - 3 e^{t} t

y = 3 e^{t} - 3 e^{t} t

\frac{d}{d x} (8 x^{5} 2 π)

\int_{1}^{4} \frac{x ^{2} + 4}{x} d x

\frac{d}{d x} (\frac{x ^{2} + 6}{( 2 x - 7 ) ^{7}})

x \to 0 lim (\frac{200 π}{x})

What is the solution for y^{''}-2y^'+y=0,y(0)=3,y^'(0)=0 ?
The solution for y^{''}-2y^'+y=0,y(0)=3,y^'(0)=0 is y=3e^t-3e^tt