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Popular >

ty^'+y=t

Solution

t y^{^{'}} + y = t

Solution

y = \frac{t}{2} + \frac{c _{1}}{t}

Solution steps

t y^{'} (t) + y = t

Solve linear ODE:

y = \frac{t}{2} + \frac{c _{1}}{t}

y = \frac{t}{2} + \frac{c _{1}}{t}

Popular Examples

derivative of f(x)=(6x^5)/5-x+3e^x derivative of

f (x) = \frac{6 x ^{5}}{5} - x + 3 e^{x}

tangent of sqrt(x),\at 36 tangent of

x, at 36

derivative of arcsec(5ln(2x))derivative of

arcsec (5 ln (2 x))

implicit (dx)/(dy),y^2=x implicit derivative

\frac{d x}{d y}, y^{2} = x

integral of 1/(64+(x-1)^2)

\int \frac{1}{64 + ( x - 1 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for ty^'+y=t ?
The solution for ty^'+y=t is y= t/2+(c_{1})/t