What is the limit as x approaches 0-of 1/(x^2+6x) ?

The limit as x approaches 0-of 1/(x^2+6x) is -infinity

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limit as x approaches 0-of 1/(x^2+6x)

x \to 0 - lim (\frac{1}{x ^{2} + 6 x})

- \infty

Solution steps

x \to 0 - lim (\frac{1}{x ^{2} + 6 x})

For

x

approaching

0

from the left

, x < 0 \Rightarrow x^{2} + 6 x < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

y = e^{x} (x^{2} - 4)

\int y 10 + 8 y - 16 y^{2} d y

\frac{d}{d x} (sin (x) + 5)

(3, 4), (6, 8)

\int_{0}^{1} (x^{2} - x^{4}) d x

What is the limit as x approaches 0-of 1/(x^2+6x) ?
The limit as x approaches 0-of 1/(x^2+6x) is -infinity