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Popular >

derivative of y=3^{cos(2x)}+e^3

Solution

derivative of

y = 3^{c o s (2 x)} + e^{3}

Solution

- 2 ln (3) \cdot 3^{c o s (2 x)} sin (2 x)

Solution steps

\frac{d}{d x} (3^{c o s (2 x)} + e^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3^{c o s (2 x)}) + \frac{d}{d x} (e^{3})

\frac{d}{d x} (3^{c o s (2 x)}) = - 2 ln (3) \cdot 3^{c o s (2 x)} sin (2 x)

\frac{d}{d x} (e^{3}) = 0

= - 2 ln (3) \cdot 3^{c o s (2 x)} sin (2 x) + 0

Simplify

= - 2 ln (3) \cdot 3^{c o s (2 x)} sin (2 x)

Popular Examples

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\int 7 sin (\frac{θ}{3}) d θ

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x \to 0 + lim (e^{x l n (x)})

Frequently Asked Questions (FAQ)

What is the derivative of y=3^{cos(2x)}+e^3 ?
The derivative of y=3^{cos(2x)}+e^3 is -2ln(3)*3^{cos(2x)}sin(2x)
What is the first derivative of y=3^{cos(2x)}+e^3 ?
The first derivative of y=3^{cos(2x)}+e^3 is -2ln(3)*3^{cos(2x)}sin(2x)