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Popular >

area y=x^2-x,y=0,x=0

Solution

area

y = x^{2} - x, y = 0, x = 0

Solution

\frac{1}{6}

+1

Decimal Notation

0.16666 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x^{2} - x d x

Solve

\int_{0}^{1} x^{2} - x d x : \frac{1}{6}

The area is:

= \frac{1}{6}

Popular Examples

derivative of sqrt(9-4x^2)

\frac{d}{d x} (9 - 4 x^{2})

integral of (3x^2-8x+5)/((x+1)^4)

\int \frac{3 x ^{2} - 8 x + 5}{( x + 1 ) ^{4}} d x

(\frac{1}{1 - x})^{^{'}}

laplacetransform e^{2t}sin(j^2t)laplace transform

e^{2 t} sin (j^{2} t)

(\partial)/(\partial x)((9+20x)y^{tan(x)})

\frac{\partial}{\partial x} ((9 + 20 x) y^{t a n (x)})

Frequently Asked Questions (FAQ)

What is area y=x^2-x,y=0,x=0 ?
The answer to area y=x^2-x,y=0,x=0 is 1/6