What is (\partial)/(\partial y)(2ky-5x) ?

The answer to (\partial)/(\partial y)(2ky-5x) is 2k

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(2ky-5x)

\frac{\partial}{\partial y} (2 k y - 5 x)

2 k

Solution steps

\frac{\partial}{\partial y} (2 k y - 5 x)

Treat

k, x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 k y) - \frac{\partial}{\partial y} (5 x)

\frac{\partial}{\partial y} (2 k y) = 2 k

\frac{\partial}{\partial y} (5 x) = 0

= 2 k - 0

Simplify

= 2 k

\int y^{- \frac{1}{3}} d y

\int \frac{5 x - 12}{x ^{3} - 6 x ^{2} + 8 x} d x

\int \frac{x - 3}{x ^{2} + 1} d x

\frac{7}{2 x + 1}, at a = 4

2 x^{3} - 6 x^{2} - 90 x + 1

What is (\partial)/(\partial y)(2ky-5x) ?
The answer to (\partial)/(\partial y)(2ky-5x) is 2k