What is the limit as x approaches 1 of (ln(x))^2 ?

The limit as x approaches 1 of (ln(x))^2 is 0

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limit as x approaches 1 of (ln(x))^2

x \to 1 lim ((ln (x))^{2})

0

Solution steps

x \to 1 lim ((ln (x))^{2})

Plug in the value

x = 1

= (ln (1))^{2}

Simplify

ln^{2} (1) : 0

= 0

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\frac{\partial}{\partial y} (y cos (x) + 2 x e^{y})

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What is the limit as x approaches 1 of (ln(x))^2 ?
The limit as x approaches 1 of (ln(x))^2 is 0