What is the solution for y^'+7y=e^{3x} ?

The solution for y^'+7y=e^{3x} is y=(e^{3x})/(10)+(c_{1})/(e^{7x)}

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y^'+7y=e^{3x}

y^{^{'}} + 7 y = e^{3 x}

y = \frac{e ^{3 x}}{10} + \frac{c _{1}}{e ^{7 x}}

Solution steps

y^{'} (x) + 7 y = e^{3 x}

Solve linear ODE:

y = \frac{e ^{3 x}}{10} + \frac{c _{1}}{e ^{7 x}}

y = \frac{e ^{3 x}}{10} + \frac{c _{1}}{e ^{7 x}}

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What is the solution for y^'+7y=e^{3x} ?
The solution for y^'+7y=e^{3x} is y=(e^{3x})/(10)+(c_{1})/(e^{7x)}