What is taylor (x-1)ln(x) ?

The answer to taylor (x-1)ln(x) is (x-1)^2-1/2 (x-1)^3+1/3 (x-1)^4-1/4 (x-1)^5+1/5 (x-1)^6+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor (x-1)ln(x)

taylor

(x - 1) ln (x)

(x - 1)^{2} - \frac{1}{2} (x - 1)^{3} + \frac{1}{3} (x - 1)^{4} - \frac{1}{4} (x - 1)^{5} + \frac{1}{5} (x - 1)^{6} + \dots

Solution steps

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( ( x - 1 ) ln ( x ) ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( ( x - 1 ) ln ( x ) ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ( x - 1 ) ln ( x ) ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 0 + \frac{0}{1 !} (x - 1) + \frac{2}{2 !} (x - 1)^{2} + \frac{- 3}{3 !} (x - 1)^{3} + \frac{8}{4 !} (x - 1)^{4} + \frac{- 30}{5 !} (x - 1)^{5} + \frac{144}{6 !} (x - 1)^{6} + \dots

Refine

= (x - 1)^{2} - \frac{1}{2} (x - 1)^{3} + \frac{1}{3} (x - 1)^{4} - \frac{1}{4} (x - 1)^{5} + \frac{1}{5} (x - 1)^{6} + \dots

\frac{\partial}{\partial x} (\frac{1}{3 x + 2})

x \to 2 - lim (g (x))

\int \frac{x}{2 x ^{2} + 1} d x

x \to \infty lim (f (x) x)

\int 8 ln (x) d x

What is taylor (x-1)ln(x) ?
The answer to taylor (x-1)ln(x) is (x-1)^2-1/2 (x-1)^3+1/3 (x-1)^4-1/4 (x-1)^5+1/5 (x-1)^6+\ldots