What is implicit (dy)/(dx),y=7x^2+6yx ?

The answer to implicit (dy)/(dx),y=7x^2+6yx is (dy)/(dx)=(14x+6y)/(1-6x)

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implicit (dy)/(dx),y=7x^2+6yx

implicit derivative

\frac{d y}{d x}, y = 7 x^{2} + 6 y x

\frac{d y}{d x} = \frac{14 x + 6 y}{1 - 6 x}

Solution steps

y = 7 x^{2} + 6 y x

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = 14 x + 6 (x \frac{d y}{d x} + y)

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{14 x + 6 y}{1 - 6 x}

\frac{d y}{d x} = \frac{14 x + 6 y}{1 - 6 x}

\int e^{- θ} cos (8 θ) d θ

\frac{\partial}{\partial x} (\frac{1}{x y ^{2} - x ^{2} y})

x \to 0 lim ((e^{x} + x)^{\frac{1}{x}})

(x + 1) \frac{d y}{d x} + y = x ln^{2} (x)

x \to \infty lim (\frac{( ln ( e ^{3 x} + x ) )}{x})

What is implicit (dy)/(dx),y=7x^2+6yx ?
The answer to implicit (dy)/(dx),y=7x^2+6yx is (dy)/(dx)=(14x+6y)/(1-6x)