What is the integral of x7^x ?

The integral of x7^x is (7^xx)/(ln(7))-(7^x)/(ln^2(7))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x7^x

\int x 7^{x} d x

\frac{7 ^{x} x}{ln ( 7 )} - \frac{7 ^{x}}{ln ^{2} ( 7 )} + C

Solution steps

\int x \cdot 7^{x} d x

Apply Integration By Parts

: \frac{7 ^{x} x}{ln ( 7 )} - \int \frac{7 ^{x}}{ln ( 7 )} d x

= \frac{7 ^{x} x}{ln ( 7 )} - \int \frac{7 ^{x}}{ln ( 7 )} d x

\int \frac{7 ^{x}}{ln ( 7 )} d x = \frac{7 ^{x}}{ln ^{2} ( 7 )}

= \frac{7 ^{x} x}{ln ( 7 )} - \frac{7 ^{x}}{ln ^{2} ( 7 )}

Add a constant to the solution

= \frac{7 ^{x} x}{ln ( 7 )} - \frac{7 ^{x}}{ln ^{2} ( 7 )} + C

\int \frac{sin ( 2 x )}{4 + cos ^{2} ( x )} d x

\int (x^{2} + x) e^{1 - 2 x} d x

\int sin (9 x) cos (6 x) d x

\frac{( x - 1 )}{x + 1}

\frac{d}{d θ} (cos^{2} (θ))

What is the integral of x7^x ?
The integral of x7^x is (7^xx)/(ln(7))-(7^x)/(ln^2(7))+C