What is the solution for (dy)/(dx)=((x^2y-y))/((y+1)) ?

The solution for (dy)/(dx)=((x^2y-y))/((y+1)) is y=\W(1/(e^{(-x^3+3x-c_{1))/3}})

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(dy)/(dx)=((x^2y-y))/((y+1))

\frac{d y}{d x} = \frac{( x ^{2} y - y )}{( y + 1 )}

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

Solution steps

\frac{d y}{d x} = \frac{( x ^{2} y - y )}{( y + 1 )}

Solve separable ODE:

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

\frac{d}{d x} (cos (4 x) + sin (4 x))

10 y^{^{''}} + 1000 y = 0

\frac{\partial}{\partial u} (2 sin (u) cos (v))

y = 4 (x + 1), y = 5 (x + 1), x = 7

x \to 0 lim (\frac{sin ( x ) - cos ( x ) sin ( x )}{x ^{2}})

What is the solution for (dy)/(dx)=((x^2y-y))/((y+1)) ?
The solution for (dy)/(dx)=((x^2y-y))/((y+1)) is y=\W(1/(e^{(-x^3+3x-c_{1))/3}})