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Popular >

y^'=3x^2(1+y^2)

Solution

y^{^{'}} = 3 x^{2} (1 + y^{2})

Solution

y = tan (x^{3} + c_{1})

Solution steps

y^{'} (x) = 3 x^{2} (1 + y^{2})

Solve separable ODE:

y = tan (x^{3} + c_{1})

y = tan (x^{3} + c_{1})

Popular Examples

derivative of (x-4/x+ln(x/4))

\frac{d}{d x} (\frac{x - 4}{x} + ln (\frac{x}{4}))

y^{''}-4y^'+3y=0,y(0)=1,y^'(0)= 1/3

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = 1, y^{^{'}} (0) = \frac{1}{3}

derivative of x^4+8x

\frac{d}{d x} (x^{4} + 8 x)

derivative of f(x)=-4/x derivative of

f (x) = - \frac{4}{x}

tangent of x^3,\at x=1 tangent of

x^{3}, at x = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=3x^2(1+y^2) ?
The solution for y^'=3x^2(1+y^2) is y=tan(x^3+c_{1})