What is area y=(14)/x ,y=-64x+72 ?

The answer to area y=(14)/x ,y=-64x+72 is -14ln(7/2)+45/2

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area y=(14)/x ,y=-64x+72

area

y = \frac{14}{x}, y = - 64 x + 72

- 14 ln (\frac{7}{2}) + \frac{45}{2}

Decimal Notation

4.96131 \dots

Solution steps

Apply the area formula:

\int_{\frac{1}{4}}^{\frac{7}{8}} \frac{14}{x} - (- 64 x + 72) d x

Solve

\int_{\frac{1}{4}}^{\frac{7}{8}} \frac{14}{x} - (- 64 x + 72) d x : - 14 ln (\frac{7}{2}) + \frac{45}{2}

The area is:

= - 14 ln (\frac{7}{2}) + \frac{45}{2}

\frac{\partial}{\partial y} (4 x^{3} y^{3} - 3 x^{2} sin (x^{3}) y)

\frac{d}{d x} (\frac{( x ^{2} - 1 ) ^{3}}{( 2 x + 1 ) ^{5}})

\int_{- 2}^{4} (x^{2} - 2 x - 8) d x

x \to \infty lim (\frac{sin ( 17 x )}{x})

\frac{\partial}{\partial x} (sin (x^{2} + x y))

What is area y=(14)/x ,y=-64x+72 ?
The answer to area y=(14)/x ,y=-64x+72 is -14ln(7/2)+45/2