What is the integral of 1/(7x+2) ?

The integral of 1/(7x+2) is 1/7 ln|7x+2|+C

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integral of 1/(7x+2)

\int \frac{1}{7 x + 2} d x

\frac{1}{7} ln ∣ 7 x + 2 ∣ + C

Solution steps

\int \frac{1}{7 x + 2} d x

Apply u-substitution

: \int \frac{1}{7 u} d u

= \int \frac{1}{7 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{7} ln ∣ u ∣

Substitute back

u = 7 x + 2

= \frac{1}{7} ln ∣ 7 x + 2 ∣

Add a constant to the solution

= \frac{1}{7} ln ∣ 7 x + 2 ∣ + C

\frac{d}{d x} (- y^{2} x)

\int cos (2 θ) d θ

f (x) = 3 x^{2} + 2 a x + b

y^{^{''}} - 2 y^{^{'}} + 5 y = 5 x + 3

x \to 3 lim (\frac{3 - x}{∣ x - 3 ∣})