What are the solutions to the equation 2(x-4)^2=26 ?

The solutions to the equation 2(x-4)^2=26 are x=sqrt(13)+4,x=-sqrt(13)+4

Find the zeros of 2(x-4)^2=26

The zeros of 2(x-4)^2=26 are x=sqrt(13)+4,x=-sqrt(13)+4

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2 (x - 4)^{2} = 26

x = 13 + 4, x = - 13 + 4

Decimal Notation

x = 7.60555 \dots, x = 0.39444 \dots

Solution steps

2 (x - 4)^{2} = 26

Divide both sides by

2

(x - 4)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 13 : x = 13 + 4

Solve

x - 4 = - 13 : x = - 13 + 4

The solutions to the quadratic equation are:

x = 13 + 4, x = - 13 + 4

x^{3} + 2 x^{2} - 3 x > 0

k^{2} - 21 k + 54

y^{2} - 5 y - 24

2 x z - 3 yz + 8 x - 12 y

\frac{8}{11} (n - 10) = 64

What are the solutions to the equation 2(x-4)^2=26 ?
The solutions to the equation 2(x-4)^2=26 are x=sqrt(13)+4,x=-sqrt(13)+4
Find the zeros of 2(x-4)^2=26
The zeros of 2(x-4)^2=26 are x=sqrt(13)+4,x=-sqrt(13)+4