What are the solutions to the equation 3t^2+t-7=0 ?

The solutions to the equation 3t^2+t-7=0 are t=(-1+sqrt(85))/6 ,t=(-1-sqrt(85))/6

Find the zeros of 3t^2+t-7=0

The zeros of 3t^2+t-7=0 are t=(-1+sqrt(85))/6 ,t=(-1-sqrt(85))/6

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3 t^{2} + t - 7 = 0

t = \frac{- 1 + 85}{6}, t = \frac{- 1 - 85}{6}

Decimal Notation

t = 1.36992 \dots, t = - 1.70325 \dots

Solution steps

3 t^{2} + t - 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 7) = 85

t_{1, 2} = \frac{- 1 \pm 85}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- 1 + 85}{2 \cdot 3}, t_{2} = \frac{- 1 - 85}{2 \cdot 3}

t = \frac{- 1 + 85}{2 \cdot 3} : \frac{- 1 + 85}{6}

t = \frac{- 1 - 85}{2 \cdot 3} : \frac{- 1 - 85}{6}

The solutions to the quadratic equation are:

t = \frac{- 1 + 85}{6}, t = \frac{- 1 - 85}{6}

3 x + 5 \leq - 7 x + 8

2 - \frac{6}{5}

ln (e^{- 1})

4 + 43 i

6 + \frac{1}{3}

What are the solutions to the equation 3t^2+t-7=0 ?
The solutions to the equation 3t^2+t-7=0 are t=(-1+sqrt(85))/6 ,t=(-1-sqrt(85))/6
Find the zeros of 3t^2+t-7=0
The zeros of 3t^2+t-7=0 are t=(-1+sqrt(85))/6 ,t=(-1-sqrt(85))/6