What are the solutions to the equation 0=70-10t-5t^2 ?

The solutions to the equation 0=70-10t-5t^2 are t=-1-sqrt(15),t=sqrt(15)-1

Find the zeros of 0=70-10t-5t^2

The zeros of 0=70-10t-5t^2 are t=-1-sqrt(15),t=sqrt(15)-1

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0 = 70 - 10 t - 5 t^{2}

t = - 1 - 15, t = 15 - 1

Decimal Notation

t = - 4.87298 \dots, t = 2.87298 \dots

Solution steps

0 = 70 - 10 t - 5 t^{2}

Switch sides

70 - 10 t - 5 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 t^{2} - 10 t + 70 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 5 ) \cdot 70}{2 ( - 5 )}

(- 10)^{2} - 4 (- 5) \cdot 70 = 1015

t_{1, 2} = \frac{- ( - 10 ) \pm 10 15}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- ( - 10 ) + 10 15}{2 ( - 5 )}, t_{2} = \frac{- ( - 10 ) - 10 15}{2 ( - 5 )}

t = \frac{- ( - 10 ) + 10 15}{2 ( - 5 )} : - 1 - 15

t = \frac{- ( - 10 ) - 10 15}{2 ( - 5 )} : 15 - 1

The solutions to the quadratic equation are:

t = - 1 - 15, t = 15 - 1

p^{2} + 12 p + 27

2 q^{2} + 3 q - 8 = 0

\frac{11}{6} - \frac{5}{8}

- 2 (x + 13) + 37 \leq 5 x - 17

x (x - 2) = 15

What are the solutions to the equation 0=70-10t-5t^2 ?
The solutions to the equation 0=70-10t-5t^2 are t=-1-sqrt(15),t=sqrt(15)-1
Find the zeros of 0=70-10t-5t^2
The zeros of 0=70-10t-5t^2 are t=-1-sqrt(15),t=sqrt(15)-1